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re: SEC Baseball Tourney- Who Goes
Posted on 5/17/19 at 9:09 am to BHMKyle
Posted on 5/17/19 at 9:09 am to BHMKyle
Three-Team Tie (or more): When three or more teams are tied for a finish, the following procedure will be used (in descending order until the tie is broken): Once the tie has been reduced to two teams, the two-team tiebreaker procedure as stated in No. 1 above will be used.
A. If all three teams are common opponents: Total won-lost percentage of games played among the tied teams.
B. Won-lost percentage of the tied teams versus the No. 1 seed and proceeding through the No. 8 seed, if necessary, using common opponents only.
C. If three or more teams still are tied, the Commissioner will conduct a draw.
A. If all three teams are common opponents: Total won-lost percentage of games played among the tied teams.
B. Won-lost percentage of the tied teams versus the No. 1 seed and proceeding through the No. 8 seed, if necessary, using common opponents only.
C. If three or more teams still are tied, the Commissioner will conduct a draw.
Posted on 5/17/19 at 9:24 am to Vecchio Cane
quote:
A. If all three teams are common opponents: Total won-lost percentage of games played among the tied teams.
Nope. They did not all play each other...
quote:
B. Won-lost percentage of the tied teams versus the No. 1 seed and proceeding through the No. 8 seed, if necessary, using common opponents only.
#1 Vanderbilt- All 3 were swept by the Commodores
#2 Arkansas- South Carolina did not play, so skip over them
#3 Mississippi St.- Kentucky did not play them, so skip over them
#4 Georgia- Bama is playing UGA now (trail series 0-1). S. Carolina was swept. Kentucky was 1-2 against Georgia.
So if Kentucky, South Carolina, and Alabama all go 0-3 this weekend, Kentucky wins the tie-breaker?
Posted on 5/17/19 at 9:31 am to Vecchio Cane
quote:
Three-Team Tie (or more): When three or more teams are tied for a finish, the following procedure will be used (in descending order until the tie is broken): Once the tie has been reduced to two teams, the two-team tiebreaker procedure as stated in No. 1 above will be used.
A. If all three teams are common opponents: Total won-lost percentage of games played among the tied teams.
B. Won-lost percentage of the tied teams versus the No. 1 seed and proceeding through the No. 8 seed, if necessary, using common opponents only.
C. If three or more teams still are tied, the Commissioner will conduct a draw.
Not sure how this:
quote:
When three or more teams are tied for a finish, the following procedure will be used (in descending order until the tie is broken):
Works with this:
quote:
A. If all three teams are common opponents: Total won-lost percentage of games played among the tied teams.
All 3 teams did not play each other (Alabama never played Kentucky); however, Alabama is 2-1 vs South Carolina and South Carolina is 2-1 vs Kentucky. That might equate to:
.667 win % for Alabama
.500 win % for South Carolina
.333 win % for Kentucky
In that scenario, Alabama gets in.
If NOT, then vs Vanderbilt:
Alabama 0-3
South Carolina 0-3
Kentucky 0-1 with two games remaining
Current #2 team Arkansas (skipped because USC did not play them):
Alabama 1-2
South Carolina - DNP
Kentucky 1-2
Current #3 team Miss State (I guess - skipped):
Alabama 0-3
South Carolina 0-1 (currently)
Kentucky - DNP
Current #4 team Georgia:
Alabama 0-1 (currently)
South Carolina 0-3
Kentucky 1-2
#5 Seed LSU(?)
Alabama 1-2
South Carolina DNP
Kentucky 0-3
So if Rule #1 doesn't apply, then it depends:
If Kentucky gets 1 win vs Vandy, they go
If Vandy sweeps Kentucky, then...
If Georgia:
Sweeps Alabama, Kentucky goes
Loses 1 to Alabama, tie breaker moves to Arkansas set, then UGA set, then... LSU? If so, Alabama goes.
Loses 2 or more to Alabama: Alabama goes
Presuming seeds remain where they are.
At least, that's how it looks to me.
This post was edited on 5/17/19 at 9:37 am
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