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re: Enigma/Word Problem/Riddle Thread - Entertain The OT
Posted on 3/6/14 at 3:52 pm to CheeseburgerEddie
Posted on 3/6/14 at 3:52 pm to CheeseburgerEddie
quote:
That is right, but do you know why? or are you just answering based on the other version you heard.
i think it establishes that it's not 6,6,1 because there is an oldest. no other way to get to 36 using 3 multipliers.
Posted on 3/6/14 at 3:52 pm to CheeseburgerEddie
It's a puzzle you must solve
Posted on 3/6/14 at 3:54 pm to CheeseburgerEddie
Is it stupid that I needed to quickly draw a flow chart hour glass diagram to complete the problem?
Posted on 3/6/14 at 3:54 pm to 3nOut
quote:
i think it establishes that it's not 6,6,1 because there is an oldest. no other way to get to 36 using 3 multipliers.
Not quite, there are lots of different ways to get to 36 with three numbers. However when the student states that the three numbers multiplying to 36 and adding to the house number is not enough information. It tells you that there must be more than one set of 3 numbers which multiply to 36 and add to the house number.
There are only two sets of numbers which multiply to 36 and add to the same number, and of those sets, you use the older child info to pick.
Posted on 3/6/14 at 4:02 pm to CheeseburgerEddie
I've heard the chocolates before so I'm not answering, but as usual the devil is in the details of the language of the question
Posted on 3/6/14 at 4:04 pm to MIZ_COU
Throw one of your own, or one you've heard before out for the OT.
Posted on 3/6/14 at 4:10 pm to CheeseburgerEddie
Old so maybe lot's have seen it
Three people check into a hotel. They pay £30 to the manager and go to their room. The manager suddenly remembers that the room rate is £25 and gives £5 to the bellboy to return to the people. On the way to the room the bellboy reasons that £5 would be difficult to share among three people so he pockets £2 and gives £1 to each person. Now each person paid £10 and got back £1. So they paid £9 each, totalling £27. The bellboy has £2, totalling £29. Where is the missing £1?
Three people check into a hotel. They pay £30 to the manager and go to their room. The manager suddenly remembers that the room rate is £25 and gives £5 to the bellboy to return to the people. On the way to the room the bellboy reasons that £5 would be difficult to share among three people so he pockets £2 and gives £1 to each person. Now each person paid £10 and got back £1. So they paid £9 each, totalling £27. The bellboy has £2, totalling £29. Where is the missing £1?
Posted on 3/6/14 at 4:21 pm to MIZ_COU
quote:
Where is the missing £1?
I took it!
Or not. The way the statement is made is a nice misdirection. Ask instead "where are the £30?", then it's more obvious: The hotel has 25, the bellboy has 2, and each of the 3 guests have 1.
Posted on 3/6/14 at 4:22 pm to MIZ_COU
Tricky...
So 25 goes to the manager.
2 goes to the bellboy.
That's the 27 quid they paid in.
There is no one extra pound.
So 25 goes to the manager.
2 goes to the bellboy.
That's the 27 quid they paid in.
There is no one extra pound.
This post was edited on 3/6/14 at 4:22 pm
Posted on 3/6/14 at 4:25 pm to MIZ_COU
They beat me to it.
We can prove that 1+1=1 if we want to. But I bet everyone has seen that.
We can prove that 1+1=1 if we want to. But I bet everyone has seen that.
Posted on 3/6/14 at 4:34 pm to CheeseburgerEddie
OK
this is an equation made up of roman numerals
I - III = II
all the lines in this eq are made from matchsticks (assume I is a single line made from a matchstick)
What are the fewest number of matchsticks you can move to make this correct?
this is an equation made up of roman numerals
I - III = II
all the lines in this eq are made from matchsticks (assume I is a single line made from a matchstick)
What are the fewest number of matchsticks you can move to make this correct?
Posted on 3/6/14 at 4:37 pm to MIZ_COU
can I move two to make it I-V=IV?
Posted on 3/6/14 at 4:38 pm to CheeseburgerEddie
you could but that's not the correct answer
Posted on 3/6/14 at 4:41 pm to MIZ_COU
The answer is one.
My proof is that Eddie was wrong with his answer of two and one is the only number lower than two and still making a move. What do I win?
My proof is that Eddie was wrong with his answer of two and one is the only number lower than two and still making a move. What do I win?
Posted on 3/6/14 at 4:41 pm to Duke
STill no correct answers
and you must show your work. No credit for guesses. This ain't the SAT
and you must show your work. No credit for guesses. This ain't the SAT
This post was edited on 3/6/14 at 4:48 pm
Posted on 3/6/14 at 4:48 pm to MIZ_COU
V-IV=I
One move plus two... umm... tilts
One move plus two... umm... tilts
Posted on 3/6/14 at 4:49 pm to finestfirst79
I thought tilts counted as moves.
I also think my move one of the sticks to turn into does not equals should be a good solution.
i-ii=/=ii
I also think my move one of the sticks to turn into does not equals should be a good solution.
i-ii=/=ii
This post was edited on 3/6/14 at 4:51 pm
Posted on 3/6/14 at 4:51 pm to CheeseburgerEddie
quote:
I also think my move one of the sticks to turn into does not equals should be a good solution.
Maybe. but it's not the correct solution. and tilts are moves. I mean the thing moved correct?
Posted on 3/6/14 at 4:53 pm to MIZ_COU
How come nobody is biting at the chocolate puzzle. Is a hint needed?
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